X^2+1,6x=0

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Solution for X^2+1,6x=0 equation:



X^2+1.6X=0
a = 1; b = 1.6; c = 0;
Δ = b2-4ac
Δ = 1.62-4·1·0
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{2.56}}{2*1}=\frac{-1.6-\sqrt{2.56}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{2.56}}{2*1}=\frac{-1.6+\sqrt{2.56}}{2} $

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